Question

how to solve this discriminant 2x² + x = 28?

Answer 1

Answer:

2x^2 + x = 28

2x^2 + x - 28 = 0

a=2 ; b=1; c=-28

b^2-4ac = 1^2-4×2(-28)

= 225

hence, the value of discriminant is 225.

Answer 2

$\star\:\:\bf\large\underline\blue{Question:-}$

• Find the discriminant of $2 {x}^{2} + x = 28$

$\star\:\:\bf\large\underline\blue{Solution:-}$

$2 {x}^{2} + x = 28$

Can be written as,

$2 {x}^{2} + x - 28 = 0$

Now,

$a = 2$

$b = 1$

$c = - 28$

Note:- a, b and c are the coefficients of the quadratic equation.

Now, discriminant of a Quadratic Equation is calculated by using the formula,

$\Delta = {b}^{2} - 4ac$

Putting the value, we get

$\Delta = {1}^{2} - 4 \times 2 \times ( - 28)$

$= 1 + 224$

$= 225$

$\bf\underline\blue{Therefore,}$

$\Delta = 225$