Question

How to solve this equation 2x^2-2x=1225

Answer 1

Answer:

2x^2+2x-1225=0

a = 2; b = 2; c = -1225;

Δ = b2-4ac

Δ = 22-4·2·(-1225)

Δ = 9804

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

The end solution:

Δ−−√=9804−−−−√=4∗2451−−−−−−−√=4√∗2451−−−−√=22451−−−−√

x1=−b−Δ√2a=−(2)−22451√2∗2=−2−22451√4

x2=−b+Δ√2a=−(2)+22451√2∗2=−2+22451√4