Math, asked by moinuddin10, 1 year ago

how to solve this equation 4x^2-12x=0

Answers

Answered by Amritanshlala

2=4x^+12x

2=16x^

16x^=2

x^=2/16

x^=8

x^=4

I hope this answer is helpful for you!!!!!!

moinuddin10: Bro sorry but the answer is wrong...anyway thx for the help bro

moinuddin10: take out 2x common for both send it to RHS . as it will get divided by 0 the RHS will remain 0. then u will have 2x-6 on LHS send 6 to the other side and divide it by 2 from x u will get the answer as 3. :)

shadowsabers03: Take out 4x as common, bro.!!!

shadowsabers03: Then you'll get x - 3 at LHS.

moinuddin10: yh ur also right ,anyway we had to find x , if u send that 3 to RHS it be x=3

moinuddin10: thx for the help tho

Amritanshlala: ooooo

Answered by shadowsabers03

$$$\sf{It's so simple!!!}$ \\ \\ \\ 4x^2-12x=0 \\ \\ 4x(x-3)=0 \\ \\ x(x-3)=\frac{0}{4} \\ \\ x(x-3)=0 \\ \\ \\ \therefore\ x=\bold{0}\ \ \ ; \ \ \ x=\bold{3}$

$$$\sf{Hope this helps. Plz mark it as the brainliest. \\ \\ Plz ask me if you've any doubts. \\ \\ \\ Thank you. :-)}$

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