how to solve this equation "o and r"
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★ Ello ★
here is your answer !!
to balance
Pb3O4 + HCL ==>. pbCl2 + H20 +Cl
★ to multiply the 8 moles of HCL
★. multiply 3 moles of pbCl2
★ multiply 4 moles of H20
we get
Pb3O4 + 8 HCL ==> 3Pbcl2 + 4H20 + Cl2
now ,
second equation
Fecl3 + NaOH ===> NaCl + Fe( OH )3
★ to balance it
★ multiply 3 moles by NaOH
★ multiply 3 moles by NaCl
★ hence
balanced chemical equation is :-
Fecl3 + 3 NaoH ==> 3 NaCl + Fe ( OH )3
hence , your question is balanced
hope it helps you dear !!!
here is your answer !!
to balance
Pb3O4 + HCL ==>. pbCl2 + H20 +Cl
★ to multiply the 8 moles of HCL
★. multiply 3 moles of pbCl2
★ multiply 4 moles of H20
we get
Pb3O4 + 8 HCL ==> 3Pbcl2 + 4H20 + Cl2
now ,
second equation
Fecl3 + NaOH ===> NaCl + Fe( OH )3
★ to balance it
★ multiply 3 moles by NaOH
★ multiply 3 moles by NaCl
★ hence
balanced chemical equation is :-
Fecl3 + 3 NaoH ==> 3 NaCl + Fe ( OH )3
hence , your question is balanced
hope it helps you dear !!!
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