Math, asked by thamimthombeni0, 3 months ago

how to solve this equation
solve for the x
(x+2)²=1

Answers

Answered by tushar64057
0

Step-by-step explanation:

(x+2)^2 =1

x^2 +4 +4x=1

x^2 +4x=1-4

x^2+4x=-3

x^2+4x+3=0

x^2+3x+1x+3=O

(x^2+3x)+(1x+3)=0

x(x+3)+1(x+3)=0

(x+1) (x+3) =0

x=-1

x=-3

Answered by sujatachannawar30
0

Answer:

(x²+ 2×x×2 +1²)=1

[identity is used:-(a+b)²=a²+2ab+b²]

x²+4x+1-1=0

x²+4x=0

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