how to solve this if AB is parrel to CD
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Step-by-step explanation:
In figure, AB || CD and EF intersecting AB and CD
∠BPQ=∠CQP (alternate angles)
So, ∠BPQ=∠CQP
5x−14=3x+34
5x−3x=14+34
2x=48
x=24
If x=24
So, ∠BPF=3x+34
=3×24+34
= 72+34=106
o
∠BPF+∠BPE=180
o
(linear pair)
106
o
+∠BPE=180
o
∠BPE=74
o
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