Question

How to solve this log .I am a beginner. hehe​

Answer 1

Answer:

answer is 1/4

Log a to the base a^n is 1/nlog a to the base a

log a to the base a is 1.so log a to the base a^n is 1/n

Answer 2

$log_{ {a}^{m} }(b) = \frac{1}{m} log_{a}(b)$

$log_{a}(a) = 1$

$by \: these \: \: 2 \: formulas \: we \: get \\ log_{ {3}^{4} }(3) = \frac{1}{4} log_{3}(3 ) = \frac{1}{4} = 0.25$

$please \: mark \: me \: as \: brilliant$