Math, asked by ankisingh9669, 8 months ago

how to solve this ?
no unnecesary answers please​

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Answers

Answered by rajutusharengineerin
1

Answer:

Step-by-step explanation:FIRSTY WE WILL ARRANGE THE TERMS AND FIND THE VALUE OF a

a²-4a+1=0

THEN FIND THE VALUE IF A AND PUT IT IN THE EQUATION

PLS MARK IT AS BRAINLIEST

Answered by cmedeepa84
1

Step-by-step explanation:

Divide the whole equation by a...

(a {}^{2}  + 1 - 4a) \div a = 0 \div a

a + (1 \div a) - 4 = 0

a + (1 \div a) = 4

 {a}^{2}  + (1 \div  {a}^{2} ) =( a + 1 \div a) {}^{2}  - 2

 =  {4}^{2}  - 2

 = 16 - 2

 = 14

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