Question

how to solve this one​

Answer 1

$a-2b+3c = 0$

$a - 2b = - 3c$

cubing on both sides,

${(a - 2b)}^{3} = {( - 3c)}^{3}$

${a}^{3} - {b}^{3} - 3ab(a - b) = - 27 {c}^{3}$

${a}^{3} - 8 {b}^{3} - 3(a)(2b)( - 3c) = - 27 {c}^{3}$

${a}^{3} - 8 {b}^{3} - 18abc= - 27 {c}^{3}$

${a}^{3} - 8 {b}^{3} + 27 {c}^{3} = 18abc$