Question

How to solve this
(p^2-q^2)^2
Whether by solving first p^2-q^2 or by directly p^4-q^4
Answer it fast ....

Answer 1

put
${p}^{2} = a$
and
${q}^{2} = b$
solve for
${(a - b)}^{2}$
then put values of a and b back and proceed. let me know if you get stuck