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Final Answer : 1) 2.5m/s
2)Displacement = -10m (opposite to initial direction)
3) t = 7s and 13s
Formula Used :
1) Average Velocity = Displacemnt / Time interval.
Steps:
1) Average velocity in first 4s,
At t =0 , x. =0
At t =4s, x = 10m
Average Velocity = (10-0)/(4-0) = 10/4=2.5m/s
2) At t =0 , x=0 m
At t =10 s, x = -10 m
Displacement = x(10s) - x(1s)
= -10-0 = -10m
Negative sign denotes,Displacement is opposite to initial direction of motion.
3) We will see time in which x = 0 .
That is, when graph touches /intersects x -axis.
=> Graph touches/intersects x - axis when
t =7s and t =13s.
Thus, Cyclist reaches it's starting point at t =7s and t =13s
2)Displacement = -10m (opposite to initial direction)
3) t = 7s and 13s
Formula Used :
1) Average Velocity = Displacemnt / Time interval.
Steps:
1) Average velocity in first 4s,
At t =0 , x. =0
At t =4s, x = 10m
Average Velocity = (10-0)/(4-0) = 10/4=2.5m/s
2) At t =0 , x=0 m
At t =10 s, x = -10 m
Displacement = x(10s) - x(1s)
= -10-0 = -10m
Negative sign denotes,Displacement is opposite to initial direction of motion.
3) We will see time in which x = 0 .
That is, when graph touches /intersects x -axis.
=> Graph touches/intersects x - axis when
t =7s and t =13s.
Thus, Cyclist reaches it's starting point at t =7s and t =13s
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