Question

how to solve this? please help me​

Answer 1

Answer:

[0,1)

Step-by-step explanation:

f(x) = x2/(1+x2)

x = 0; f(x) = 0

x = -1 ; f(x) = 1/2

x = 1 ; f(x) = 1/2

x = 2 ; f(x) = 4/5 <1

x = 3 ; f(x) = 9/10 <1

i,e.. f(x) never reach 1

hence Range f(x) = [0,1)

Note : denominator is more than Numerator hence a proper fraction (+ve) never becomes 1