Question

how to solve this problem​

Answer 1

Answer:

According to the problem ab and bc are equivalent with ac

Therefore, ac = √ (5)^2 - 4^2 = 3 cm = 3 x 20^(-2) m

Now let the force given on ac is f

f = Blℓ sinθ

here B is the magnetic field I is current

I is given as 2 A

Therefore

f = 2 x B x 3 x 10^(-2) x sin 90

= B x 6 x 10^(-2) N

Therefore the acceleration will be a = f/m = B x 6 x 10^(-2) /10 x 10^(-3) = 6Bm/s^2

Here is your answer mate...

Hope it helps !!!