how to solve this problem
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in the question, a=20cm,c=14cm,b=d=6cm
let a line de has been drawn which is parallel to BC and equal to BC=6cm
hence EB=CD=14
and ae=20-14=6
the triangle ∆aed is a equilateral.
now h be the perpendicular on ae at o from d
then for ∆aod,
h=√ad^2-do^2=√6^2-3^2=√36-9=√27=3√3cm
let a line de has been drawn which is parallel to BC and equal to BC=6cm
hence EB=CD=14
and ae=20-14=6
the triangle ∆aed is a equilateral.
now h be the perpendicular on ae at o from d
then for ∆aod,
h=√ad^2-do^2=√6^2-3^2=√36-9=√27=3√3cm
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abhishek12341:
sorry but it is wrong
i dont know the right answer, but i tried to do my best
can u plz tell me how did u get the height=5cm?
don't worry I will do it
uttu
your answer s wrong
Answered by
0
firstly we find area of trapezium . it is the correct answer hope it will helps you
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hl
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