Question

how to solve this problem​

Answer 1

Answer:

8^3×8^4/(2^5)^3 = 8^(3+4)/(2^(5×3)

8^7/2^15 = (2^3)^7/2^15

=2^(3×7)/2^15

=2^21/2^15

=2^(21-15) = 2^6 = 64

Answer 2

$= \frac{ ({ {2}^{3} })^{3} \times ({2}^{3})^{4}}{ { ({2}^{5}) }^{3} }$

$= \frac{ {2}^{3 \times 3} \times {2}^{3 \times 4} }{ {2}^{5 \times 3} }$

$= \frac{ {2}^{9} \times {2}^{12} }{ {2}^{15} }$

$= \frac{ {2}^{12 + 9} }{ {2}^{15} }$

$= \frac{ {2}^{21} }{ {2}^{15} }$

$= {2}^{21 - 15}$

$= {2}^{6} = 64$

Hence, you can solve the problem by applying laws and identities of exponents.