How to solve this problem
Attachments:
Answers
Answered by
1
Resultant of F2 and F3
angle=90°
so F=√(F2)^2+(F3)^2+2F2F3cos90
F=√(F2)^2+(F3)^2
acceleration=F/m=[√(F2)^2+(F3)^2]/m
And direction=opposite of F1
angle=90°
so F=√(F2)^2+(F3)^2+2F2F3cos90
F=√(F2)^2+(F3)^2
acceleration=F/m=[√(F2)^2+(F3)^2]/m
And direction=opposite of F1
Similar questions