Question

how to solve this problem

Answer 1

here is your answer ⤵️

Given ➡️ density =1.02 g/cm³

____ Molarity of H2SO4 =1.35M.

Now.....,

$d \: = M \: ( \frac{1}{m} + \frac{M' \: }{1000} )$

1.02 = 1.35(1/m+98/1000)

m = 1.53 mol/kg.

Therefore molality is 1.53 mol/kg.

Answer 2

Kya mst joke maara h ree Baba ...

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