how to solve this problem can any one help me to do this problem
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180 -( 60 +90)
= 180 - 150
= 130 degree is required measure of angle
= 180 - 150
= 130 degree is required measure of angle
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Sum of all angle of triangle = 180°
Thus,
∠OPQ + ∠OQP + ∠POQ = 180°
90° + ∠OQP + 60° = 180°
∠OQP = 180 - 90 - 60
∠OQP = 30°
Thus,
∠OPQ + ∠OQP + ∠POQ = 180°
90° + ∠OQP + 60° = 180°
∠OQP = 180 - 90 - 60
∠OQP = 30°
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