Math, asked by dhanushsakthi, 1 year ago

how to solve this problem in simple method

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Answered by Anonymous
5

solution

( \frac{x {}^{b} }{x {}^{c} } ) {}^{ \frac{1}{bc} }   \times ( \frac{x {}^{c} }{x {}^{a} } ) { }^{ \frac{1}{ca} }  \times  (\frac{x {}^{a} }{x {}^{b} } ) {}^{ \frac{1}{ab} }  \\  =  x {}^{ \frac{b - c}{bc} }  \times x {}^{ \frac{c - a}{ca} }  \times x {}^{ \frac{a - b}{ab} }  \\  = x {}^{ \frac{b - c}{bc} +  \frac{c - a}{ca}   +  \frac{a - b}{ab} }  \\  = x {}^{ \frac{a(b - c) + b(c - a) + c(a - b)}{abc} }  \\  = x {}^{ \frac{ab - ac + bc - ab + ac - bc}{abc} }  \\  = x {}^{ \frac{0}{abc} }  \\  = x {}^{0}  \\  = 1

Answered by Anonymous
1

Answer:

\huge\begin{lgathered}( \huge\frac{x {}^{b} }{x {}^{c} } ) {}^{ \huge\frac{1}{bc} } \times ( \huge\frac{x {}^{c} }{x {}^{a} } ) { }^{ \huge\frac{1}{ca} } \times (\huge\frac{x {}^{a} }{x {}^{b} } ) {}^{ \huge\frac{1}{ab} } \\ = x {}^{ \huge\frac{b - c}{bc} } \times x {}^{ \huge\frac{c - a}{ca} } \times x {}^{ \huge\frac{a - b}{ab} } \\ = x {}^{ \huge\frac{b - c}{bc} + \frac{c - a}{ca} + \frac{a - b}{ab} } \\ = x {}^{ \huge\frac{a(b - c) + b(c - a) + c(a - b)}{abc} } \\ = x {}^{ \huge\frac{ab - ac + bc - ab + ac - bc}{abc} } \\ = x {}^{ \huge\frac{0}{abc} } \\ = x {}^{0} \\ = 1\end{lgathered}

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