Question

how to solve this problem s

Answer 1

hey mate I am sending an attachment please wait


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Answer 2

Hola Mate!❤❤

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This question is based on Number Systems, Grade 9.

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Here is your answer,

→ $\frac{1}{\sqrt{7} }$

→ $\frac{1}{\sqrt{7} } \frac{\sqrt{7} }{\sqrt{7} }$

→ $\frac{\sqrt{7} }{7}$

Here √7 × √7 becomes 7 because, the roots are cut.

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→ $\frac{1}{\sqrt{7}-\sqrt{6}  }$

→ $\frac{1}{\sqrt{7}-\sqrt{6}  } \frac{\sqrt{7} - \sqrt{6}  }{{\sqrt{7} - \sqrt{6}  }}$

→$\frac{\sqrt{7} + \sqrt{6}  }{\sqrt{7^{2} - \sqrt{6}^2 } }$

(Here we write a² - b² becuase, (a+b)(a-b) = a² - b²)

→ $\frac{\sqrt{7}+\sqrt{6}  }{\sqrt{7}^2 - \sqrt{6}^2  }$

→ ${\sqrt{7}+\sqrt{6}$

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→ $\frac{1}{\sqrt{5} +\sqrt{2}   }$

→ $\frac{1}{\sqrt{5} +\sqrt{2}   }\frac{(\sqrt{5} -\sqrt{2})}{(\sqrt{5} -\sqrt{2})}$

→ $\frac{\sqrt{5}- \sqrt{2}  }{5 - 2}$

→ $\frac{\sqrt{5}- \sqrt{2}  }{3}$

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→ $\frac{1}{\sqrt{7}-2 }$

→ $\frac{1}{\sqrt{7}-2 } \frac{\sqrt{7}+2 }{\sqrt{7}+2 }$

→ $\frac{\sqrt{7}+2 }{7 - 4}$

→ $\frac{\sqrt{7}+2 }{3}$

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Hope it helps!

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