how to solve this Q
[1-{1-(1-n)^-1}^-1]^-1
the answer is 'n'
but how ?
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1 - [1-(1-n) ^-1]^-1]^-1
= 1-[1-1/1-n]^-1]^-1
= 1-[ 1-n/-n]^-1
=[ -1/-n]^-1
=-n/-1
or n
= 1-[1-1/1-n]^-1]^-1
= 1-[ 1-n/-n]^-1
=[ -1/-n]^-1
=-n/-1
or n
Anonymous:
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