Question

How to solve this qstn?​

Answer 1

$\large\underline{\pmb{\sf{\diamond{\; Given \;that...}}}}$

• Potential difference=40V

• Resistance=8Ω

• Time=2min

$\large\underline{\pmb{\sf{\diamond{\; Need\:to\: find...}}}}$

• Current flowing

• Charges passes through resistor

$\large\underline{\pmb{\sf{\diamond{\; Formula\: used...}}}}$

• I=Q/t

• V=IR (ohms law)

$\large\underline{\pmb{\sf{\diamond{\; Solution...}}}}$

Let's apply ohm's law to find current!

• V=IR

By substituting given values:

⇒ 40V=I(8Ω)

⇒ (40V)/(8Ω)=I

⇒ 5V/Ω=I

⇒ 5 Ampere=I

So the value of current is 5 Ampere.

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Now we will applying formula for finding no. Of charges:

• I=Q/t

By substituting given values:

⇒ 5 Ampere=Q/(2min)

Now we know that 1 min=60 seconds, so 2 min will be=2×60=120 seconds.

⇒ 5 Ampere=Q/120

⇒ (5 Ampere)×120 seconds=Q

⇒ 600 Ampere.seconds=Q

⇒ 600c=Q

So the required value of charge is 600 coulomb.

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$\large\underline{\pmb{\sf{\diamond{\; Remember \;that...}}}}$

• Volt/ohm=Ampere

• Ampere. Seconds=Coulomb

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