Question

how to solve this question​

Answer 1

Answer:

The given equation of line is

$x - 5y = 3 \: \: \: \: \: \: \: \: \: ..........(i)$

As,

we know that ,

at x axis y co-ordinate is equals to zero.

So,

Putting x = 0 in equation

(i)

we get,

$- 5y = 3 \\ \\ y = - \frac{3}{5}$

So,

it will cut y-axis at

$(0, \frac{ - 3}{5} )$

Now,

let x axis Y co-ordinate is zero

So,

eq (i) will be

$x = 3$

So,

point where the given line cuts x-axis will be

(3,0)

Answer 2

Question:

Find the points where the graph of the equation

x-5y=3 cuts the x-axis and y-axis

Explanation:

Given equation is

$\sf x-5y=3$

we have to find the points where the straight line of the equation cuts the x-axis and y-axis

so,

we know that a point on x-axis has y-coordinate 0

so put y=0 in the equation

$\longrightarrow \: x - 5(0) = 3 \\ \\ \longrightarrow \boxed{ \sf \: x = 3}$

So it cuts x-axis at the point (3,0)

And for a point on y-axis x-coordinate is 0

so put x=0

$\longrightarrow \: 0 - 5y = 3 \\ \\ \longrightarrow \boxed{ \sf \: y = \dfrac{ - 3}{5} }$

It cuts the y-axis at the point (0,-3/5)