Math, asked by justMeetjoshionly, 11 months ago

how to solve this question​

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Answered by Anonymous
22

SOLUTION:-

Given:

The parallelogram where coordinates of the three vertices given in order are (-3,2), (-5,-3),(3,-3).

To find:

The coordinates of the fourth vertex of parallelogram.

Explanation:

Let the coordinates of fourth vertex be D (R,M).

We know that, In a ||gm diagonal bisect to each other.

So,

The midpoint of BD= Midpoint of AC.

We have,

Given three vertices of a parallelogram are;

  • A(-3,2)
  • B(-5,-3)
  • C(3,-3)
  • D(R,M)

Mid-point of line segment joining the points (R1,M1) & (R2, M2) is;

( \frac{R1 + R2}{2}  , \frac{M1 + M2}{2} ) Mid-point of AC:

( \frac{ - 3 + 3}{2}  \:  \frac{2 - 3}{2} ) \\  \\ ( \frac{0}{2}  , \frac{ - 1}{2} )

Mid-point of BD = Mid-point of AC

Therefore,

Mid-point of BD:

( \frac{ - 5 + R}{2}  \:  \frac{ - 3 + M}{2} ) =  (\frac{0}{2}  \:  \frac{ - 1}{2} ) \\  \\  \frac{ - 5 + R}{2}  =  \frac{0}{2}  \\  \\  - 5 + R = 0 \\  \\ R = 5

&

 \frac{ - 3 + M}{2}  =  \frac{ - 1}{2} \\  \\  - 3 + M =  - 1 \\  \\ M =  - 1 + 3 \\  \\ M = 2

Therefore,

The fourth vertex of ||gm, D is (5,2).

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