Question

how to solve this question??...................

Answer 1

With 3/5 of the usual speed,

Man reaches destination 2 1/2 hrs late, that is, 5/2 = 2.5 hrs

Let us suppose,

S = usual speed

T = usual time

D = distance to office,

So

* S = slower speed

T + 2.5 = time when walking at slower speed

Since the distance to the office is a constant, as distance remains the same whether he walks slower of faster,

So we can say ,

S * T = (3/5 ) S * ( T + 2.5 )

ST = (  3/5 ) S * ( T + 2.5 )

ST = ( 3/5) ST + 1.5 S

Divide both sides by ST

= ( 3/5) ST / ST +

1 = 3/5+ 1.5/t

1 -3/5 = 1.5/t

2/5 =  1.5/t

T =  1.5/(2/5)

= 1.5 * ( 5/2  )

T = 3 . 75 hours

Hence,

His usual time to reach the destination is 3.75 hours