how to solve this question
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Answered by
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Answer:
b^2-4ac
=(2a-b-c)^2-4(a+b-2c)(c+a-2b)
=4a^2+b^2+c^2-4ab+2bc-4ac -4ac-4ab-16bc-4a^2+8ab
-4ab+8b^2+8c^2
=9b^2+9c^2-4ab-14bc-8ac
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