Math, asked by imrahul24, 10 months ago

how to solve this question ​

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Answers

Answered by akshayaakshaya184
5

Answer:

b^2-4ac

=(2a-b-c)^2-4(a+b-2c)(c+a-2b)

=4a^2+b^2+c^2-4ab+2bc-4ac -4ac-4ab-16bc-4a^2+8ab

-4ab+8b^2+8c^2

=9b^2+9c^2-4ab-14bc-8ac

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