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nice question
........
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Step-by-step explanation:
[x^(a+b)/x^c]^(a-b) [x^(b+c)/x^a]^(b-c) [x^(c+a)/x^b]^(c-a)
=x^(a^2-b^2)-(ac-bc) +(b^2-c^2)-(ab-ca)+(c^2-a^2)-(bc-ab)
since a^m /a^n=a^(m-n) , a^m x a^n=a^(m+n)
=x^0
=1
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