how to solve this question
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cotA= 1/tanA and tanA=sinA/cosA ...so
cotA = cosA/sinA
cotA = cosA/sinA
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tanA =1/cotA
sinA=1/ root(cot²A-1)
secA= root(cot²A+1)/cotA
sinA=1/ root(cot²A-1)
secA= root(cot²A+1)/cotA
jeisuggaj:
and could u please explain this sinA please if u had time
cosec2-cot2=1 so cosec2=1+cot2.......now put 1/sin2 in place of cosec2 n u'll get it...well the previous answer is wrong as u hv to express all this in terms of cot only.
s i figured that point myself but what the thing is i am getting is sinA=1/√1+cotsquareA
thats y
any ways thank u miss
oh yah sorry...u'r r8..thnx 4 pointing out the mistake
hmm.nice.
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