Question

how to solve this question ​

Answer 1

Answer:

$\frac{bc}{ \sqrt{ {b}^{2} + {c}^{2} } }$

Step-by-step explanation:

let AD= x

from ∆DBA and ∆ABC

$\frac{x}{c} = \frac{b}{ \sqrt{ {b}^{2} + {c}^{2} } }$

$x = \frac{bc}{ \sqrt{ {b}^{2} + {c}^{2} } }$

Answer 2

Answer:

let AD= x

from ∆DBA and ∆ABC

\frac{x}{c} = \frac{b}{ \sqrt{ {b}^{2} + {c}^{2} } }

c

x

=

b

2

+c

2

b

x = \frac{bc}{ \sqrt{ {b}^{2} + {c}^{2} } }x=

b

2

+c

2

bc