Question

how to solve this question? ​

Answer 1

Answer:

$\Huge{\underline{\underline{\mathbf{\color{plum}{Answer}}}}}$

Given: focal length of a concave mirror is 8cm.The object is placed at 16cm in front of the mirror.

To Find:

the position of image and it's nature?

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$\bold\blue{★According\: to \:the\: question }$

➼ Mirror = concave

➼ Focal Length = 8cm

➼ Distance of the object = 16cm

Now,

As the mirror is concave so, the nature of the image will be inverted and real.

As we know that!

$| \frac{1}{u} + \frac{1}{v} = \frac{1}{f} |$

Where,

The focal length in taken in negetive terms as it is a concave mirror.

Here!

U Stands for Distance of the object

V Stands for Distance of the image

F stands for Focal length

Now,

Distance of the image (U) = -16

Focal length = - 8cm

$\bold\red{Substituting \:the \:values\:we\:get}$

$= \frac{1}{u} + \frac{1}{v} = \frac{1}{f}$

$= \frac{1}{ - 16} + \frac{1}{v} = \frac{1}{ - 8}$

$= \frac{1}{v} = \frac{1}{ - 8} + \frac{1}{16}$

$= \frac{1}{v} = \frac{ - 16}{128} + \frac{8}{128}$

$= \frac{1}{v} = \frac{ - 16 + 8}{128}$

$= \frac{1}{v} = \frac{ - 8}{128}$

$= \frac{1}{v} = - 16cm$

Henceforth,

The Distance of the image is 16cm respectively

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