how to solve this question
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given two zeroes are √2 and -√2
their factors are (x-√2) and (x+√2)
their factors product is (x-√2)(x+√2)
=x²-2
divide p(x) with x^2-2
x²-2)2x^4-3x^3-3x^2+6x-2(2x^2-3x+1
2x^4+0x^3-4x^2
- - +
-3x^3+x^2+6x
-3x^3+0x^2+6x
+ - -
x^2-2
x^2-2
- +
0
their factors are (x-√2) and (x+√2)
their factors product is (x-√2)(x+√2)
=x²-2
divide p(x) with x^2-2
x²-2)2x^4-3x^3-3x^2+6x-2(2x^2-3x+1
2x^4+0x^3-4x^2
- - +
-3x^3+x^2+6x
-3x^3+0x^2+6x
+ - -
x^2-2
x^2-2
- +
0
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