how to solve this question ??
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1
a) ∠ACB=180°-110°=70°
b) ∠BAC=180-(60+70)=50°
2
a) ΔABD= 180-(35+35)=110°
so, ∠b=180-110=70°
b)ΔACB=180-(46+46)=88°
so, ∠c=180-88=92°
c)ΔABC=180-(92+70)=22°
so ∠DAE=35+22+46=103°
hope this helps you!
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