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First recall that cos3(2x)=(cos(2x))3
So,
ddx(cos3(2x))=3cos2(2x)ddx(cos(2x))
=3cos2(2x)(−sin(2x))ddx(2x)
=3cos2(2x)(−sin(2x))(2)
=−6cos2(2x)sin(2x)
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So,
ddx(cos3(2x))=3cos2(2x)ddx(cos(2x))
=3cos2(2x)(−sin(2x))ddx(2x)
=3cos2(2x)(−sin(2x))(2)
=−6cos2(2x)sin(2x)
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