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A wire has a resistance of 2.25 Ω. Calculate the resistance of another wire, made from the same material, whose length is 10 times more and its area of cross-section is 4 times less as compared to given wire.
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hmmm it ws vry difficult ..i try it bt i don;t find the answr sry..
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R1 = 2.25 Ω.
R2 = ?
R1/R2 = (L1*A2)/(L2*A1)
L2 = 10L1
A2 = A1/4
2.25/R2 = 1/40
R2 = 90 Ω.
R2 = ?
R1/R2 = (L1*A2)/(L2*A1)
L2 = 10L1
A2 = A1/4
2.25/R2 = 1/40
R2 = 90 Ω.
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