how to solve this question.... answer is B
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4
total number of chits= 10
chits kept aside= 1
chits remaining = 10 - 1
=9
now probablity of 9 is = 1
and total numbers remaining = 9
now probality is = 1/9
t7t:
thanks
Answered by
2
Hey mate
your answer is....
Option.c(1/90)
Step by step explaination:
event=n(E)=1
total classes=n(S)=10*9=90
->p(E)=1/90
hope it helps
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