Question

how to solve this question
(can use any method)​

Answer 1

Answer:

$\huge\mathtt{Solution:-}$

In eq (1)

$\mathtt\blue{ \frac{x}{2} + y = 0.8}$

$\mathtt\blue{ \frac{x + 2y}{2} = 0.8 }$

$\mathtt\blue{x + 2y = 0.8 \times 2}$

$\mathtt\blue{x + y = 1.6 \: \: \: \: \: \: \: \: \: \: \: \: }$

In eq (2)

$\mathtt\blue{ \frac{7}{x + \frac{y}{2} } = 10 \: \: \: (do \: cross \: multiply) }$

$\mathtt\blue{7 = 10( x + \frac{y}{2}) }$

$\mathtt\blue{7 = 10x + 5y \: \: \: \: \: \: \: \: \: \: \: eq(2)}$

Now multiply eq 1 by 10 both sides

$\mathtt\purple{10(x + y) = 10(1.6)}$

$\mathtt\purple{10x + 10y = 16 \: \: \: \: \: \: \: \: \: \: \: eq(1)}$

Now use elimination method

$\mathtt\purple{10x + 20y = 16}$

$\mathtt\purple{10x + 5y = 7}$

Subtract both equations

$\mathtt \green{15y = 9}$

$\mathtt\green{y = \frac{9}{15} }$

$\mathtt\green{y = \frac{3}{5} }$

Now substitute y value in eq(2)

$\mathtt\green{10x + 5 \times \frac{3}{5} = 7 }$

$\mathtt\green{10x +3 = 7}$

$\mathtt\green{10x = 7 - 3}$

$\mathtt\green{10x = 4}$

$\mathtt\green{x = \frac{4}{10} }$

$\mathtt\green{x = \frac{2}{5} }$

Step-by-step explanation:

I hope this helps you mate.