how to solve this question . i could not able to solve
Attachments:
PARI1111111:
is it the full question??
yes it is the full question
k..
Answers
Answered by
0
let theta be x for better typing
So, 3sinx+4cosx=5
Squaring both sides,
9sin^2 x +16cos^2 x + 24sinxcosx = 25
9+7cos^2 x + 24sinxcosx =25
7cos^2 x +24sinxcosx = 16
7 - 7sin^2 x + 12sin(2x) = 16
12sin(2x) - 7sin^2 x = 9
Now, you can solve for sinx
So, 3sinx+4cosx=5
Squaring both sides,
9sin^2 x +16cos^2 x + 24sinxcosx = 25
9+7cos^2 x + 24sinxcosx =25
7cos^2 x +24sinxcosx = 16
7 - 7sin^2 x + 12sin(2x) = 16
12sin(2x) - 7sin^2 x = 9
Now, you can solve for sinx
i think the squaring will also be considered for x..
Similar questions