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Now, lim (x → 0) [ {log (1 + x³)}/sin³x]
= lim (x → 0) [{log (1 + x³)/x³}/{(sin³x)/x³}]
= lim (x → 0) {log (1 + x³)/x³}/[lim (x → 0) (sinx)/x]³
= 1/1
= 1
Since, lim (x → 0) log(1 + x)/x = 1
and lim (x → 0) sinx/x = 1
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Now, lim (x → 0) [ {log (1 + x³)}/sin³x]
= lim (x → 0) [{log (1 + x³)/x³}/{(sin³x)/x³}]
= lim (x → 0) {log (1 + x³)/x³}/[lim (x → 0) (sinx)/x]³
= 1/1
= 1
Since, lim (x → 0) log(1 + x)/x = 1
and lim (x → 0) sinx/x = 1
#MarkAsBrainliest
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