Question

How to solve this question
If A is the sum of the digits of 4444^4444 and B is the sum of the digits of A then f‌ind the sum of the digits
of B.

Answer 1

Answer:

The approach is to use the fact that 4444≡7(mod9), so that 44443≡1(mod9), and then get 44444444≡7(mod9).

Then use the fact that for any integer N, the sum of the digits of N is equivalent to N(mod9).

Finally use logs to base 10 to get a limit on the size of A, hence B etc.

The answer is 7, if I remember correctly

Step-by-step explanation:

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