how to solve this question in exam..
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Construct center point O and another triangle AOE and triangle OBD prove conference that's ae = bd
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heyy here is ur..
write the intersection point of be and ab be o
given: angle d and angle e = 90,,ad = be
to prove: ae = bd
proof: then in tri AEO and tri BOD
ao = bo ( ad = be )
oe = od ( ad = be )
angle d = angle e ( each 90° )
by rhs congruency
triangle AEO =~ BOD
so by cpct AE = BD
hope it helps u...if it did plzz mark me brainliest...thanks...!!!
write the intersection point of be and ab be o
given: angle d and angle e = 90,,ad = be
to prove: ae = bd
proof: then in tri AEO and tri BOD
ao = bo ( ad = be )
oe = od ( ad = be )
angle d = angle e ( each 90° )
by rhs congruency
triangle AEO =~ BOD
so by cpct AE = BD
hope it helps u...if it did plzz mark me brainliest...thanks...!!!
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