how to solve this question in substitution method
5x+3y=21;2x-y=4
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from eq 2 y= 2x-4
sub eq 2 in eq 1
5x+3(2x-4)= 21
5x+6x-12 =21
11x= 21+ 12
11x=33
x=3
sub x=3 in eq 2
2(3)-y=4
6-y=4
y=6-4
y=2
therefore x=3 , y=2 are answers
sub eq 2 in eq 1
5x+3(2x-4)= 21
5x+6x-12 =21
11x= 21+ 12
11x=33
x=3
sub x=3 in eq 2
2(3)-y=4
6-y=4
y=6-4
y=2
therefore x=3 , y=2 are answers
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