Question

How to Solve this Question
$if \: u = {sin}^{ - 1} \frac{y}{x}$

$\frac{du}{dx} = \\ \frac{ {dx}^{2} }{dydx} =$
$\frac{du}{dy} = \\ \frac{ {d}^{2} u}{ dxdy } =$
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Answer 1

Answer:

i don't know iam so sorry

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