Question

how to solve this questions ................................​

Answer 1

$\frac{ {(48)}^{ - 2} \times {(64)}^{1 \div 2} }{ {(24)}^{ - 1} } \\ = \frac{ \frac{1}{ {48}^{2} } \times \sqrt{64} }{ \frac{1}{ {24}^{1} } } \\ = \frac{ \frac{1}{2304} \times 8}{ \frac{1}{24} } = ( \frac{1}{2304} \times 8)( \frac{24}{1} ) \\ = \frac{24}{288} = \frac{12}{144} = \frac{1}{12} = \frac{1}{ {12}^{ 1} } \\ = 1 \times {12}^{ - 1} \\ = {12}^{ - 1}$

Answer 2

Hello !!

For you answer this question, you only need make use of this method below. See the resolution.

$\mathsf{\dfrac{48^{-2}\times64^{\frac{1}{2}}}{24^{-1}}} \\\\\\ \mathsf{=\dfrac{\left(\frac{1}{48^{2}}\right)\times\sqrt{64}}{\left(\frac{1}{24}\right)}} \\\\\\ \mathsf{=\dfrac{\left(\frac{1}{2304}\right)\times8}{\left(\frac{1}{24}\right)}} \\\\\\ \mathsf{=\dfrac{\left(\frac{1}{2304}\right)\times\left(\frac{8}{1}\right)}{\left(\frac{1}{24}\right)}} \\\\\\ \mathsf{=\dfrac{\left(\frac{8}{2304}\right)}{\left(\frac{1}{24}\right)}} \\\\\\ \mathsf{=\left(\frac{8}{2304}\right)\times\left(\frac{24}{1}\right)} \\\\\\ \mathsf{=\dfrac{192}{2304}} \\\\\\ \mathsf{=\dfrac{1}{12}} \\\\\\ \boxed{\bf\red{=\mathsf{12^{-1}}}}$

Final result : (3) 12^(-1).

I hope I have collaborated !