Question

how to solve this roots of quadratic equation
X2+19x+60=0​

Answer 1

Answer:

Step-by-step explanation:

I HAVE ATTACHED THE SOLUTION...

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Answer 2

QUESTION:

SOLVE THE ROOTS OF QUADRATIC EQUATION.

${x}^{2} + 19x + 60 = 0$

ANSWER:

GIVEN EQUATION IS IN THERE FORM OF

$a {x}^{2} + bx + c.$

STEP 1.

WE HAVE TO SPLIT THE MIDDLE TERM ON SUCH A WAY THAT IT'S SUM IS b ie.19 and product is a.c which is 1×60.

${x}^{2} + 15x + 4x + 60$

so. 15+4= 19

15×4 = 60

STEP 2.

NOW WE TAKE THE COMMON FACTOR.

${x}^{2} + 15x + 4x + 60 \\ x(x + 15) + 4(x + 15)$

SO THE FACTORS ARE:

$(x + 4)(x + 15)$

x =-4.

x =-15.

FINAL ANSWER:

-4 AND -15

PLZ MARK AS BRAINLIEST!!!!!