Math, asked by Globalfriend, 1 year ago

How to solve this Simultaneous equation by elimination method?
6x+15y=3
6x-4y=60

Answers

Answered by ItzMysticalBoy
0

Answer:

 \:  \:  \:  \: 6x + 15y = \:  \:   \:  \:  3 \\ \:  \:  \:  \:  6x - \ \:  4 y    = \:   \:  60 \\  -   \:  \:  \:  \:  \:  \:  +   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: - \\\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   19y  = - 57 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  y   \:  =  \frac{ - 57}{19}  \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  y  \: =  - 3

Putting value of y :

 \:  \:  \:  \:  \:  \:  \: 6x + 15y = 3

 =  >  6x + 15 \times ( - 3)= 3

 =  > 6x + ( - 45) =  3

 =  > 6x - 45 = 3

 = >  6x = 3 + 45

 =  > 6x = 48

 =  > x =  \frac{48}{6}

 =  > x = 8

Answered by Anonymous
0

\huge{\bf{ \red{\fbox{ \color{blue}{Answer :-}}}}}

6x + 15y = 3 ........(1)

6x - 4y = 60 .........(2)

Usimg equation 1 and 2

6x + 15y = 3

6x - 4y = 60 (Changing sign )

- + -

_________

19y = - 57

y = -57/19

y = -3

\huge{\bf{ \green{\fbox{ \color{blue}{y = -3}}}}}

Put Value of y in equation 2.

6x - 4(-3) = 60

6x + 12 = 60

6x = 60 - 12

6x = 48

x = 48/6

x = 8

\huge{\bf{ \green{\fbox{ \color{blue}{x = 8}}}}}

\huge{\ddot{\red{\smile}}}

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