How to solve this simultaneously
4a-2b= -12
-3a-3b= 7
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hey mate here is your answer
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substitute method
4a=-12+2b
a= (-12+2b)/4
-3((-12+2b)/4)+3b-7
(−3/2)b+9+3b-7
(-3/2)b+3b +9-7
(3/2) b+2
b= 2 × 2/3
b= 4/3 (or) 1.33
substitute
-3a-3b=7
-3a-3(4/3)=7
-3a-4=7
-3ea=7+4
a= -11/3 (or) -3.66
Verification
-3a-3b=7
-3(-11/3)-3(4/3)=7
11-4=7
7=7
L.H.S= R.H.S
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