Question

how to solve this sum​

Answer 1

hope this will help u and the answer attached is correct

Answer 2

Answer:

$(i)\frac{2}{-3}\\\\(ii)\frac{5}{-7}$

Step-by-step explanation:

$\textbf{To know:}$

Any Number raise to 0 = 1 i.e n⁰ = 1

Any Number raise to -ve Power when reciprocated Turns into +ve Power i.e

$n^{-1} = \frac{1}{n}^1\\\\\\eg~=>~(\frac{4}{5})^{-4}=(\frac{5}{4})^4$

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Here is how we solve the sum :

(i)

$= 90^0*(\frac{-3}{2})^{-1}\\\\= 1 * \frac{2}{-3}\\\\= \frac{2}{-3}$

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(ii)

$=(\frac{-7}{5})^{-1}/7^0\\\\= \frac{5}{-7}/\frac{1}{1}\\\\=\frac{5}{-7}$

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Hope it helps you mate :)