How to solve this sum 6√12÷√3×3√2
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Answered by
0
6√12÷√3×3√2
=6×3.4641÷1.7320×3(1.4142)
=20.7846÷7.3481
=2.8287
OR
[tex]\frac{6 \sqrt{2}* \sqrt{2}* \sqrt{3} }{ \sqrt{3}* \sqrt{2}*3 } = \frac{6 \sqrt{2} }{3} [/tex]-------[since √3 and √2 get cancelled out].
=6×3.4641÷1.7320×3(1.4142)
=20.7846÷7.3481
=2.8287
OR
[tex]\frac{6 \sqrt{2}* \sqrt{2}* \sqrt{3} }{ \sqrt{3}* \sqrt{2}*3 } = \frac{6 \sqrt{2} }{3} [/tex]-------[since √3 and √2 get cancelled out].
vivek2001:
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6√12÷√3×3√2 = 6x (√4x3) / √3 x 3√2
=6x2√3 / √3 x 3√2
= 4 / √2
=2√2
=6x2√3 / √3 x 3√2
= 4 / √2
=2√2
Answered by
0
6√12÷√3×3√2 = 6x (√4x3) / √3 x 3√2
=6x2√3 / √3 x 3√2
= 4 / √2
=2√2
=6x2√3 / √3 x 3√2
= 4 / √2
=2√2
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