Question

How to solve this to get cos2theta / sin2theta​

Answer 1

Answer:

Firstly take L.H.S.(left hand side),

i.e.

L

H

S

=

1

−

(

sin

2

θ

1

−

cos

θ

)

=

1

−

[

1

−

cos

2

θ

1

−

cos

θ

]

=

1

−

[

1

2

−

(

cos

θ

)

2

1

−

cos

θ

]

=

1

−

⎡

⎢

⎢

⎣

(

(

1

+

cos

θ

)

)

(

1

−

cos

θ

)

(

1

−

cos

θ

)

⎤

⎥

⎥

⎦

so after solving it will give,

=

1

−

(

1

+

cos

θ

)

=

1

−

1

−

cos

θ

which will give,

=

cos

θ

=

R

H

S

hence proved.

Step-by-step explanation:

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Answer 2

• that ans I hope it's correct answer