how to solve this
who will be the right will be marked as brainliest
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golu46:
send full pic of ur que...
Answers
Answered by
3
Given:-
[1] AB=CD
[2] angle OCD> angle COD
[3] angle OAB>angle AOB
R.T.P:-
OB>OD
PROOF:-
angle OCD>angle COD
OD>CD-------(1)
angle OAB< angle AOB ( opposite angles to greater sides are greater)
OB<AB
OB<CD (AB=CD) given
OB<OD [from(1)]
(proved)
[1] AB=CD
[2] angle OCD> angle COD
[3] angle OAB>angle AOB
R.T.P:-
OB>OD
PROOF:-
angle OCD>angle COD
OD>CD-------(1)
angle OAB< angle AOB ( opposite angles to greater sides are greater)
OB<AB
OB<CD (AB=CD) given
OB<OD [from(1)]
(proved)
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Answered by
0
Proof
In Triangle OCD angle OCD greater than angle COD
OD greater than CD
In ∆AOB angle AOB greater than anglw OAB
AB greater than OB
OD greater than OB
OD greater than AB (CD = AB )
AB graeter than OB
OB greater than OB ( proved)
In Triangle OCD angle OCD greater than angle COD
OD greater than CD
In ∆AOB angle AOB greater than anglw OAB
AB greater than OB
OD greater than OB
OD greater than AB (CD = AB )
AB graeter than OB
OB greater than OB ( proved)
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